第一个方法：
declare @max integer,@id integer
declare cur_rows cursor local for
select 主字段,count(*) from 表名 group by
主字段 having count(*) > 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
发生这种重复的原因是表设计不周产生的，增加唯一索引列即可解决。
2.这类重复问题一般要求保留重复记录中的第1条记录，假设有重复的字段为Name,Address，
要求得到这两个字段唯一的结果集：
select identity(int,1,1) as autoID,
* into #Tmp from tableName
select min(autoID) as autoID
into #Tmp2 from #Tmp group by Name,
autoID select * from #Tmp where autoID
in(select autoID from #tmp2)
